3z+(3z-z^2)(3-3z+z^2)=3z

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Solution for 3z+(3z-z^2)(3-3z+z^2)=3z equation:



3z+(3z-z^2)(3-3z+z^2)=3z
We move all terms to the left:
3z+(3z-z^2)(3-3z+z^2)-(3z)=0
We add all the numbers together, and all the variables
(3z-z^2)(3-3z+z^2)=0

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